Example
In the following graph, a vehicle is travelling
at a constant speed of 4m/s for
a time duration of 5 seconds.
What distance is travelled by the vehicle ?
Distance = Speed x Time
so D = 4 m/s x 5 s
= 20 m
If we calculate the area of the graph,
then A = LB
A =5 x 4
A = 20 units2
Example
In the following graph, a vehicle starts at rest,
accelerates to a speed of 4m/s after 3 seconds,
maintains this speed for 3 seconds then decelerates
to a standstill over a time duration of 45 seconds.
What distance is travelled by the vehicle ?
This time, there are 3 distinct areas to consider:-
Total area = 26 units2
The vehicle travels 26 m.
How can this be checked ?
where
For the left hand triangle
so
For the rectangle
For the right hand triangle
so
The vehicle does indeed travel 26 m.
Example
In the following graph, a vehicle starts at rest
and accelerates :
What distance is travelled by the vehicle during the first 4 seconds ?
This is more of a challenge.
Split the curve into intervals of ½ seconds and draw
rectangles to find upper and lower bounds of the area.
v = 0.5t2
Time (s) |
t |
0.5 |
1 |
1.5 |
2 |
2.5 |
3 |
3.5 |
4 |
Speed (m/s) |
v |
0.125 |
0.5 |
1.125 |
2 |
3.125 |
4.5 |
6.125 |
8 |
The lower bound of the area under the curve
is the sum of the areas of the rectangles drawn to
the right of the curve.
Area = 0.5(0+0.125+0.5+1.125+2+3.125+4.5+6.125)
Area = 0.5 x 17.5 = 8.75 units2
The upper bound of the area under the curve
is the sum of the areas of the rectangles drawn to
the left of the curve.
Area = 0.5(0.125+0.5+1.125+2+3.125+4.5+6.125+8)
Area = 0.5 x 25.5 = 12.75 units2
The true area under the graph lies somewhere
between these two values.
Increasing the number of rectangles helps:-
Eventually, both the upper and lower bounds converge to a limit.
This limit is the area under the graph.
Here, the area is converging to 10.67 units2
The area between the graph of the function y = f(x)
and the x-axis, starting at x = 0 is called the area function A(x)