Differential Equations

These equations, containing a derivative, involve rates of change – so often appear in an engineering or scientific context.
Solving the equation involves integration.

 

The order of a differential equation is given   by the  highest derivative used.

The degree of a differential equation is given  by the  degree of the  power of the highest derivative used.

Examples

    1

Types of differential equations :-

 

 

First order Differential Equations

Solving by direct integration

The general solution of differential equations of the form
2 can be found using direct integration.
Substituting the values of the initial conditions will give

Example

Solve the equation

6

  3

4

5

 

Example

 Find the particular solution of the
differential equation

7
   given  y = 5 when x = 3

 

8

9

 

Example

 A straight line with gradient 2 passes through
the point  (1,3). Find the equation of the line.

   10

11

 

Variables Separable

A variables separable differential equation is one
in which the equation can be written with all the terms
for one variable on one side of the equation, and the other
terms on the other side.

12 13

Example

  Find the general solution of the differential equation

     14      

  15

Example

 Find the general solution of the differential equation

    16  

17

 

Example

 Find the particular solution of the differential equation

   18  

  given y = 2 when x = 1

  

19

Partial fractions are required to break the left hand side of the equation into a form which can be integrated.

20

so

21

which integrates to general solution

22

substitute values for particular solution

23

 

Linear  Differential Equations

 These are first degree differential equations.

24

   describes a  general linear differential equation  of order n,
where an(x), an-1(x),etc and f(x) are given functions of x or constants.

Louis Arbogast introduced the differential operator
D = d/dx  , which simplifies the general equation to

 26

or

 25

If f(x) = 0 , the equation  is called homogeneous.
If f(x) ≠0 , the equation is non-homogeneous

 

First order Linear  Differential Equations

To solve equations of the form

27

1) Express in standard form

28
where  P and Q are functions of x or constants

2) Multiply both sides by the Integrating Factor 29

3) Write 30

 

4) Integrate the right hand side,

use integration by parts if necessary

32

 

5) Divide both sides by the integrating factor.
This gives the General solution.

6) Use any initial conditions to find
particular solutions.

 

Example

Find a general solution of the equation

    32

    34

   35

36

so

37

38

 

Example

Find a general solution of the equation

  39

   where x ≠2 , and hence find the particular solution
for y = 1 when x=-1

 40

41

42

 

Second order  Linear Differential Equations

To solve equations of the form

43

1) Write down the auxiliary equation
am2 +bm + c = 0         

2) Examine the discriminant of the auxiliary equation.

3) For real and distinct roots,  m1 and m2,

the general solution is

44

4) For real and equal roots,
the general solution is

45

 

5)For complex conjugate roots,
   m1= p + iq  and m2 = p - iq  ,
the general solution is

46

6) Use any initial conditions to find the particular solution.

 

Example

 Find the general solution of the equation

  47

  and the particular solution for which
y = 7 when x=0 and dy/dx = 7

48

   51

49

52

50

Example

  Find the general solution of the equation

   53

  and the particular solution for
y=0 and dy/dx = 3 when x=0

54

    55

56

57

58

    

Example

 Find the general solution of the equation

  59

   60

61

 

Second order non – homogeneous Differential Equations

      The solution to equations of the form

      62

          has two parts, the complementary function (CF)
and the particular integral (PI).

so Q(x) = CF +PI

The CF is the general solution as described above
for solving homogeneous equations .

 The Particular Integral is found by substituting
a form similar to Q(x) into the left hand side equation,
and equating co-efficients.

The PI cannot have the same form as any of the terms in the CF,
so care has to be taken to ensure that this is not the case.
In such a situation, an extra x term is usually introduced to the PI.

  A particular solution is found by substituting initial conditions into the general solution. Do not just use the CF!!!

Example

Find the general solution of the equation

  63  

64

 65

  66   

67

Example

  Find the general solution of the equation

    68

  and the particular solution for
y=0 and dy/dx = 5 when x=0

69

70

  71

72

Now, substitute these back into the original equation

73

  74

75

Now find the particular solution

76

77

 

Phew!!

 

© Alexander Forrest