Trigonometry is the study of triangles.
The sides of any right angled triangle can be labelled Hypotenuse, Adjacent and Opposite.

The hypotenuse is always opposite the right angle.It is the longest side of the triangle.
The adjacent is the side that forms part of the required angle.
The opposite is the side directly across from the required angle.
The ratio of these sides are given special names:
sine, cosine and tangent.
These are shortened to sin, cos and tan
To find an angle or side , follow this recipe :-
1. Find and sketch the triangle
2.
3. Identify and mark angle to be used / found
4. Label Opposite, Hypotenuse and Adjacent
5. Write out ratio
6. Write down solution
Always draw a sketch
Calculate angle θ˚, the glide path of the aircraft.
Give your answer correct to one decimal place.

1. Find and sketch the triangle
2.
3. Identify and mark angle to be used / found
4. Label Opposite, Hypotenuse and Adjacent

5. Write out ratio

6. Write down solution
The angle of the glide path of the aircraft is 20.1˚ (1dp)
How high above the ground is the aircraft ?
Give your answer correct to one decimal place.

1. Find and sketch the triangle
2.
3. Identify and mark angle to be used / found
4. Label Opposite, Hypotenuse and Adjacent

5. Write out ratio

6. Write
down solution
The height of the aircraft is 115.5m (1dp)
A skier is racing down a 150m long ramp.
How high above the ground is the starting flag ?

1. Find and sketch the triangle
2.
3. Identify and mark angle to be used / found
4. Label Opposite, Hypotenuse and Adjacent

5. Write out ratio

6. Write
down solution
The starting flag is 50m above ground.
A skier is racing down a ramp which is 200m long.
The start of the ramp is 100m above ground level.
What is the value of θ˚, the angle of the ramp?

1. Find and sketch the triangle
2.
3. Identify and mark angle to be used / found
4. Label Opposite, Hypotenuse and Adjacent

5. Write out ratio

6. Write
down solution
A ship is at anchor. The chain is 150 m long and makes an angle of 30˚ from the anchor point to the seabed. The anchor point is 5m above the water level. How deep in the water is the anchor ? Give your answer to the nearest metre.

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solution

A ship is taut at anchor. The chain is 150 m long and lies 75m from the anchor point. What is the value of θ˚, the angle from the seabed to the anchor point at the ship’s bow ?



How high up the wall is the ladder ?
(Give your answer
to 2d.p.)
1.
Find and sketch the triangle
2.
3. Identify and mark angle to be used / found
4. Label Opposite, Hypotenuse and Adjacent
5. Write out
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6.
ü ü ü ü
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Two
Tick Test
Tick what you know Adjacent
Tick what you want Opposite
Look for two ticks
use that ratio. ( Here, use tan)
7. Write out ratio
Alternative for
credit level


8. Write down solution
The ladder is 1.73m (2dp) up the wall.
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The space shuttle needs tying down due to expected high winds. The distance between the tie down points is 100m. The cable is kept taut at an angle of 45˚.
What total length of cable is needed for the tie down ?
Give your answer correct to the nearest cm.

Solution

The cable makes an isosceles triangle between the tie down points on the ground.
